The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased by 2, the fraction becomes 3/4. What is the original fraction?
Which of the following systems of equations can be used to solve the problem?
n + 4 = 3 and d + 5 = 4
3n - 2d = 0 and 4n + 2 = 3d + 2
3n = 2d and 4n + 8 = 3d + 6

Respuesta :

Let the numerator be x, and the denominator be y. 

The ratio of the numerator to the denominator of a fraction is 2 to 3. 

>> x/y = 2/3 

If both the numerator and the denominator are increased by 2, the fraction becomes 3/4. 

>> (x + 2)/(y + 2) = 3/4 

From x/y = 2/3, x = (2/3)y 

From (x + 2)/(y + 2) = 3/4, cross multiply and we have 

4(x + 2) = 3(y + 2) 

Substitute x = (2/3)y into the equation above. 

4[(2/3)y + 2] = 3(y + 2) 

Distribute the lefh hand side and solve for y. 

(8/3)y + 8 = 3y + 6 

(8/3)y - 3y = 6 - 8 

-(1/3)y = -2 

y = 6 

x = (2/3)y = (2/3)(6) = 4 

Hence the numerator is 4, and the denominator is 6. 

Hope this helps!

Answer:

3n = 2d and 4n + 8 = 3d + 6

Step-by-step explanation:

The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased by 2, the fraction becomes 3/4.  

Let n be the numerator and d be the denominator

The ratio of the numerator to the denominator of a fraction is 2 to 3

[tex]\frac{n}{d} =\frac{2}{3}[/tex]

Corss multiply it , the equation becomes

3n = 2d

If both the numerator and the denominator are increased by 2, the fraction becomes 3/4.  

add 2 with n  and d

[tex]\frac{n+2}{d+2} =\frac{3}{4}[/tex]

Cross multiply it

4(n+2) = 3(d+2)

4n+8 = 3d+6