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How many milliliters of magnesium metal, with a density of 1.74 g/mL, are needed to produce 102.3 grams of magnesium oxide in the single-replacement reaction below? Show all steps of your calculation as well as the final answer

Mg + H2O → MgO + H2

Respuesta :

moles MgO = 102.3 g/40.304 g/mol=2.54 

the ratio between MgO and Mg is 1 : 1 

moles Mg = 2.54 

mass Mg = 2.54 mol x 24.305 g/mol=61.7 g 

V = mass / density = 61.7 g/ 1.74 g/mL=35.5 mL

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