contestada

When N identical capacitors are connected in series across a battery, the energy stored is U. If the same capacitors were connected in parallel across the same battery, then how much energy would be stored?
NU
N2U
U/N
U

Respuesta :

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

capacitors are connected in series 

same q same V1=V/N

U1=1/2 C*(V/N)^2

U(total-1)=N*U1=C*V^2/2N

capacitors connected in parallel

same V

U2=1/2 C*V^2

U(total-2)=1/2 N*C*V^2


U(total-2)/U(total-1)= C*V^2/2N/N*C*V^2/2=>U(total-2)=N^2* U(total-1)

Otras preguntas