Did you mean sin^2xcos^2x=(1-cos4x)/8?
Because I have my solution here to that problem:
sin²(x)*cos²(x) = 1/8*(1-cos(4x))
[sin(2x)/2]² = 1/8*(1-cos(4x))
sin²(2x)/4 = 1/8*(1-cos(4x))
Recall that sin²(x) = (1-cos(2x))/2
From this, we can tell that sin²(2x) = 1-cos(4x)/2
[(1-cos(4x)/2]/4 = 1/8*(1-cos(4x))
(1-cos(4x))/8 = (1-cos(4x))/8
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
