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The Math Club is sponsoring a bake sale. If their goal is to raise at least $200, how many pies must they sell at $4.00 each in order to meet that goal? Write, solve, and graph an inequality that represents this situation.

A 4.00p<_200;p<_50
<---------------------------x------------> closed going to left from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

B. 4.00p<_200;p<_50
<---------------------------x-------------> open going to left from positive 50
-125 -100 -75 -50 -25 0 25 50 75 10 125

C 4.00p>_200;p>_50
<---------------------------x---------------> open going to right from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

D 4.00p>_200;p>_50
<--------------------------------------------> closed going to the right from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

Respuesta :

I going to have to say d

Answer:

D. [tex]4.00p\geq 200;p\geq 50[/tex]  

Step-by-step explanation:

We have been given that The Math Club's goal sells each pie for $4.00, so the money raised from 'p' pies would be 4.00p.

We are also told that their goal is to raise at least $200. This means that money raised from 'p' pies should be greater than or equal to 200. We can represent this information in an inequality as:

[tex]4.00p\geq 200[/tex]

Now, we will solve for 'p' by dividing both sides of our inequality by 4.00.

[tex]\frac{4.00p}{4.00}\geq \frac{200}{4.00}[/tex]

[tex]p\geq 50[/tex]

Upon graphing our inequality we will get our desired graph as shown in the attached file.

Since 'p' is greater than or equal to 50, so our line will have a solid dot on 50 and it will go in positive direction that is right. Therefore, option D is the correct choice.

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