divacasey09
contestada

What is the equation of the line that is the perpendicular bisector of the segment
with (10,-15) and (-10, 25) as endpoints?
y= kx + 10
y= kx + 5
y= -x + 10
y = 2x + 5

Respuesta :

mhanifa

Answer:

  • y= kx + 5

Step-by-step explanation:

Perpendicular bisector passes through the midpoint of the line.

The midpoint is:

  • x = (10 - 10)/2 = 0
  • y = (-15 + 25)/2 = 5

Slope of the line:

  • m = (25 - (-15))/(-10 - 10) = -2

The line perpendicular to this has to have a slope of 1/2 as perpendicular lines have opposite-reciprocal slopes.

Use point-slope form and point (0, 5) to find the equation of the line:

  • y - 5 = 1/2(x - 0)
  • y = 1/2x + 5

Correct option seem B as others don't match ours

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