Answer:
[tex]m=397.6gC_8H_{18}}[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, we can set up the heat of reaction per mole of gasoline as shown below:
[tex]\Delta H=\frac{-10,990kJ}{2molC_8H_{18}}=-5495\frac{kJ}{molC_8H_{18}}[/tex]
Now, since the total heat is obtained by multiplying the moles and heat of reaction, we can calculate the moles as shown below:
[tex]n=\frac{Q}{-\Delta H } \\\\n=\frac{19,126kJ}{-(-5495\frac{kJ}{molC_8H_{18}} )} \\\\n=3.48molC_8H_{18}}[/tex]
Finally, since the molar mass of gasoline is 114.22 g/mol, we can easily calculate the mass as follows:
[tex]m=3.48molC_8H_{18}} *\frac{114.22gC_8H_{18} }{1molmolC_8H_{18}} } \\\\m=397.6gC_8H_{18}}[/tex]
Best regards!
