Answer:
[tex]m_{Co}=6998g=7.0kg[/tex]
Explanation:
Hello there!
In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:
[tex]Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})[/tex]
Thus, we solve for the mass of cobalt as shown below:
[tex]m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg[/tex]
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