contestada

PLeaseee ITS Timedddd + BrainlIESTT
A 6.50 gram piece of aluminum reacts with an excess of oxygen. use the balanced equation below to determine how many grams of aluminum oxide is formed during this reaction.
4 Al + 3 O2 --> 2 Al2O3
a. 662.7 grams of Al2O3
b. 6.1 grams of Al2O3
c. 24.6 grams of Al2O3
d. 12..3 grams of Al2O3

Respuesta :

jufsanabriasa

Answer:

d. 12.3 grams of Al2O3

Explanation:

Based on the reaction:

4Al + 3O2 → 2Al2O3

Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.

To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

Moles Al -Molar mass: 26.9815g/mol-

6.50g * (1mol / 26.9815g) = 0.241 moles Al

Mass Al₂O₃ -Molar mass: 101.96g/mol-

0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

0.120 moles Al2O3 * (101.96g / mol) =

12.3g of Al2O3 are produced.

Right answer is:

d. 12.3 grams of Al2O3

Otras preguntas