Answer:
0,1
Step-by-step explanation:
Let n represent the first interger. and n+1 represent the next interger.
[tex]n \times (n + 1) = 0[/tex]
[tex] {n}^{2} + n = 0[/tex]
Complete the square.
[tex]( \frac{n}{2} {)}^{2} = \frac{ {n}^{2} }{4} [/tex]
[tex] {n}^{2} +n + \frac{ {n}^{2} }{4} = \frac{ {n}^{2} }{4} [/tex]
[tex](n + \frac{n}{2} ) {}^{2} = \frac{n {}^{2} }{4} [/tex]
Take the square root.
[tex](n + \frac{n}{2} ) = \frac{n}{2} [/tex]
[tex]n = 0[/tex]
Plug 0 in for 0+1.
[tex]0 + 1 = 1[/tex]
So the consective intergers are 0,1.
