kobby86 kobby86

21-04-2021
Chemistry

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Calculate the ph of 0.62 NaOH

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keijosalonen keijosalonen

21-04-2021

Answer: 13.79

Explanation: c(NaOH) = 0.62 mol/l, andc(OH-) = 0.62 mol/l.

Because pH +pOH = 14.00 and pOH = -log(OH) = -log(0.62) = 0.2076

Then PH= 14.00-0.2076 = 13.79

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