Answer:
[tex]M_{acid}=0.16M[/tex]
Explanation:
Hello there!
In this case, according to the reaction between hydrochloric acid and sodium hydroxide:
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
Whereas the 1:1 mole ratio of the acid to base allows us to write:
[tex]n_{acid}=n_{base}[/tex]
At the equivalence point (complete neutralization); it is possible for us to write it in terms of molarities and volumes as follows:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
In such a way, we solve for the molarity of the HCl to obtain:
[tex]M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\M_{acid}=\frac{83mL*0.45M}{235mL}\\\\M_{acid}=0.16M[/tex]
Best regards!
