The first term of a geometric sequence is 8 and the fourth term is 216. What is the sum of the first 12 terms of the corresponding series? A. 2,125,760 B. 6,377,288 C. 236,192 D. 708,584

Respuesta :

Answer:

2,125,760

Step-by-step explanation:

The first term (a) is 8

The fourth term is 216

Hence the sum of the first 12 term can be calculated as follows

= 8-8(3)^12/1-3

= 8-24^12/-2

= 2,125,760

The sum of first 12 terms is 2,125,760

Sum of the first 12 term  =  2,125,760

For geometric sequence,

aₙ = arⁿ⁻¹

where

a = first term

r = common ratio

n = number of terms

Therefore,

a = 8

a₄ = 216

let's find the common ratio

216 = 8 × r⁴⁻¹

216 = 8 × r³

r³ = 216 / 8

r³ = 27

r = [tex]\sqrt[3]{27}[/tex]

r = 3

Let's find sum of the first 12 terms.

Sₙ = a (rⁿ - 1) / r - 1

S₁₂ = 8(3¹² - 1) / 3 - 1

S₁₂ = 8(531440) / 2

S₁₂ = 4251520 / 2

S₁₂ = 2,125,760

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