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Calculate the pH for a 1.0 x 10-5 M solution of OH at 25°C.
pH = -log[H*), pOH = -log[OH-]
14 = pH + POH
0 pH = 11.00
0 pH = 9.00
0 pH = 6.00
0 pH = 3.00

Respuesta :

mousahmussa

Answer:

ph=9.00

Explanation:

Given 1.0x10^-15M of OH at 25c

first find Poh from Poh=-log[OH]

then Poh=-log[1.0x10^-5]

from above Ph=5

then find Ph from ph+poh =pw

where pw=14

so

ph+5=14

ph=9.00

The pH for a 1.0 x 10-5 M solution of OH at 25°C is 9.

What is pH?

  • pH is a measure of acidity and basicity of aqueous solution.
  • The range of pH goes from 0 - 14, with 7 being neutral.
  • pH of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base.
  • pH is the measure of the relative amount of free hydrogen and hydroxyl ions in aqueous or other solutions.

In water pH + pOH=14

pH = 14 - pOH = 14 - 5 = 9

From definition, pOH = - log₁₀ [OH⁻]  

Thus pOH = -log₁₀ (1 x 10⁻⁵)

                  = - (-5) = 5

pH + pOH = 14

pH = 14 - pOH

     = 14 - 5 = 9  

pH = 9

Hence, pH = 9 is the correct answer.

To learn more about pH here

https://brainly.com/question/23051665

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