Answer:
226 fishes and 274 chicken
Step-by-step explanation:
Given
[tex]n = 500[/tex] --- anticipated orders
See attachment for table
Required
Number of fish and each to order
First, we calculate the proportion of each
This calculated by dividing the number of each by the total.
From the table, we have:
[tex]Fish = 153[/tex]
[tex]Chicken = 186[/tex]
[tex]Total = 339[/tex]
So, the proportion is:
[tex]P(Fish) = \frac{153}{339}[/tex]
[tex]P(Fish) = \frac{51}{113}[/tex]
[tex]P(Chicken) = \frac{186}{339}[/tex]
[tex]P(Chicken) = \frac{62}{113}[/tex]
In an anticipated order of 500, the number of order of each is:
[tex]Fish = P(Fish) * n[/tex]
[tex]Fish = \frac{51}{113} * 500[/tex]
[tex]Fish = \frac{51* 500}{113}[/tex]
[tex]Fish = \frac{25500}{113}[/tex]
[tex]Fish \approx 226[/tex]
[tex]Chicken = n - Fish[/tex] ---- Compliment rule
[tex]Chicken \approx 500 - 226[/tex]
[tex]Chicken \approx 274[/tex]
