Answer: The new pressure of the balloon is 108 kPa
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 105 kPa
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 2510000 L
[tex]V_2[/tex] = final volume of gas = 2600000 L
[tex]T_1[/tex] = initial temperature of gas = [tex]122^0C=(122+273)K=395K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]150^0C=(150+273)K=423K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{105\times 2510000}{395}=\frac{P_2\times 2600000}{423}[/tex]
[tex]P_2=108kPa[/tex]
The new pressure of the balloon is 108 kPa
