1) Solve.

Manny invested $1,200 at a simple interest rate of5%(0.05). How much money would he have after 7 years?


2)Solve.

Approximately how much money would Manny have if he invested $1,200 at an interest rate of 5% for 7 years compounded monthly (12 times a year)?


3) Solve.

If the value of a stock depreciates at 3% a year, what will a $100 investment be worth in 20 years?


4) Solve.

Iodine-131 has a half-life of 8 days. How much would be left of an original 40g sample after 40 days?


5) Use elimination to find the answer, and then choose the correct answer.

A restaurant is offering a special deal on pizza and drinks. You can get 2 large pizzas and 4 large drinks for $16. Or, you can get 4 large pizzas and 7 large drinks for $30. How much would each pizza (p) and each drink (d) cost separately?




Respuesta :

Step-by-step explanation:

1. Given : P = $1200 , R = 5%, T = 7 years

   Therefore, the simple interest is, [tex]$SI = \frac{PTR}{100}$[/tex]

                                                                [tex]$=\frac{1200 \times 7 \times 5}{100}$[/tex]

                                                                 = $ 420

   Therefore, total amount Manny will have is A = P + Si

                                                                                = 1200 +420

                                                                                = $ 1620

2. Given : P = $1200 , r = 5%, t = 7 years, n = 12 times (compounded)

   So the amount is :

  [tex]A=P\left(1+\frac{r}{n}\right)^{nt}[/tex]

  [tex]A=1200\left(1+\frac{0.05}{12}\right)^{12\times 7}[/tex]

      = 1692.17

  So Manny would have approximately $ 1692 when compounded monthly.

3. Given :

  The amount of stock = $ 100

   rate of depreciation = 3%

    Time = 20 years.

    Therefore, using compound interest, we get

    Future value = initial value x [tex]$(1-\text{rate})^{number of years}$[/tex]

                          = [tex]$100 \times (1 - 3 \%)^{20}$[/tex]

                          = 54.38

  So after 20 years, the value would be $ 54.38

4. Given :

  Initial amount, i = 40 gram

  time, t = 40 days

  half life of the isotope, h = 8 days

  1/2 is used because of half life

  Therefore, the final amount is given by :

  [tex]$a=i \times \left(\frac{1}{2}\right)^{t/h}$[/tex]

  [tex]$a=40\times \left(\frac{1}{2}\right)^{40/8}$[/tex]

    = 1.25 gram

 So after 40 days, 1.25 gram will be left.

5. Let  p =  pizza and d = drink

   So according to the question,

    2p + 4d = $ 15 ....(i)

    4p + 7d = $ 30...(ii)

   Equation equation (i) and (ii), we get

   d = $0

   and p = $ 7.5