Answer:
a) attached below
b) i) 0.82 ii) 7
c) 40 mL
Explanation:
A) Titrate 20 mL of 0.15 M HCL with 0.15 M NaOH
sketch attached below
B) Determine PH at
i) start of titration
conc of H^+ = 0.15 M
HCL ------- > H^+ + CL^-
∴ pH = - log ( H^+ ) = - log ( 0.15 ) = 0.82
ii) equivalence point
at equivalence point the moles of acid = moles of base hence pH at equivalence = 7
C) Determine the total volume of solution at the equivalence point
volume of base at equivalence point
= Ma Va = Mb Vb
∴ Vb = ( Ma * Va ) / Mb
= ( 0.15M * 20 mL ) / 0.15
= 20.0 mL
Total volume of solution at equivalence point = Ma + Mb = 20 + 20 = 40 mL
