Respuesta :
Answer:
Explanation:
(a) Force constant = force/displacement = 15/0.2
=75 N/m
(b) For SHM with spring, the angular frequency = sqrt ( force constant / mass )
= sqrt ( 75 / 1.8 )
= 6.455
Frequency = Angular frequency / 2pi
= 1.03Hz
(c) Maximum speed is when object's potential energy is at minimum.
1/2*mass*speed^2 = 1/2*force constant*displacement^2
speed^2 = 75*0.2^2/1.8 = 1.67
speed = sqrt (1.67)
= 1.29 m/s
(d) It occurs at x=0
(e) Maximum acceleration = Force / m = 15/1.8
= 8.33 m/s^2
(f) It occurs at x=0.2m
Answer:
Explanation:
given:
The mass of the object attached to the spring: m = 1.80 kg
The magnitude of the maximum horizontal force exerted: F = 15.0 N
The amplitude of the spring-object oscillation: A = 0.200 m
a. k=15/.2=75N/m
b. (2pi*frequency)^2 = k/m = 75/1.8 = 41.67
frequency = 1.03Hz
c. max speed^2 = amplitude^2*k/m = 0.2^2 * 41.67
max speed = 1.29 m/s
d. x=0m
e. max accel = F/m = 15/1.8 = 8.33 m/s^2
f. x=0.2m
e. energy = 1/2*k*A^2
= 1/2*75*0.2^2
= 1.5J