Answer:
a) Level of significance [tex]\alpha = 0.01[/tex]
b) Standard normal
[tex]p = 0.75[/tex]
[tex]Z = 0.62[/tex]
c) Â
[tex]P = 0.5352[/tex]
d) Â
[tex]P > \alpha[/tex]
e) We fail to reject null hypothesis Â
Step-by-step explanation:
Let us say
The null hypothesis H_0 is p= 0.70 which means that Probability of arresting male of age ranging between 15 to 34 years is 0.7
Alternate hypothesis H_1 is p not equal to 0.7 which means that Probability of arresting male of age ranging between 15 to 34 years is not equal to 0.7
a) For 1% level of significance [tex]\alpha = 0.01[/tex]
b) Standard normal
[tex]n_p > 5\\n_q >5[/tex]
[tex]p = \frac{24}{32} = 0.75[/tex]
[tex]Z = \frac{(0.75-0.70)}{\sqrt{\frac{(0.7*0.3)}{32} } } = 0.62[/tex]
c) Â
[tex]P = 2 * 0.2676 = 0.5352[/tex]
d) Â
[tex]P > \alpha[/tex]
e) We fail to reject null hypothesis Â
Hence, there is not enough data to prove that at 1% level of significance the probability of number of male arrested between age 15-34 is  0.70