Step-by-step explanation:
The endpoints of the diameter are A(-4,1) and B(4,2) . For finding the equation of circle we need to find the centre and the radius.
Coordinates of centre can be find out by the midpoint formula.
[tex] \implies Center = \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\implies Centre = \bigg(\dfrac{-4+4}{2},\dfrac{1+2}{2}\bigg)\\\\\implies \boxed{\boxed{Centre = (0 , 1.5)}}[/tex]
Now the measure of radius can be obtained by half the distance between them.
[tex]\implies D = \sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}\\\\\implies D =\sqrt{ (4+4)^2+(2-1)^2}\\\\\implies D = \sqrt{ 64 + 1 }\\\\\implies D =\sqrt{65} \\\\\implies \boxed{\boxed{ Radius = \dfrac{\sqrt{65}}{2} }}[/tex]
We know the general equation of circle as ,
[tex]\implies (x-h)^2+(y-k)^2= r^2[/tex]
- (h,k) is centre
- r is radius.
[tex]\implies (x-0)^2+ (y-1.5)^2 = \bigg(\dfrac{\sqrt{65}}{2} \bigg)^2\\\\\implies x^2 + (y-1.5)^2=\dfrac{65}{4} \\\\\implies\boxed{\boxed{ 4x^2+4(y-1.5)^2 = 65 }}[/tex]
