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A bag contains Green and Yellow Switch. Two Switch are drawn without
replacement. The probability of selecting a Green Switch and then a Yellow Switch
is 0.39. The probability of selecting a Green Switch on the first draw is 0.4. What
is the probability of selecting a Yellow Switch on the second draw, given that the
first Switch drawn was Green?

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Answer:

0.975

Explanation:

Given that:

Let

green switch = G

Yellow switch = Y

P(G) and then P(Y) = 0.39

P(G) on first draw = 0.4

The probability of selecting a yellow on second draw :

P(G on First draw) * P(Y on second draw) = 0.39

Divide both sides by 0.4

0.4 * P(Y on second draw) = 0.39

P(Y on second draw) = 0.39 / 0.4

P(Y on second draw) = 0.975

Hence, the probability of selecting yellow on second draw is 0.975

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