Answer:
[tex]T=8\times 10^{-19}\ s[/tex]
Explanation:
Given that,
The frequency of x-ray is, [tex]f=1.25\times 10^{18}\ Hz[/tex]
We need to find the time period of these x-rays. Let it is be T. We know that, the relation between f and T is given by :
T = 1/f
So,
[tex]T=\dfrac{1}{1.25\times 10^{18}}\\\\=8\times 10^{-19}\ s[/tex]
So, the time period of these x-rays is equal to [tex]8\times 10^{-19}\ s[/tex].
The time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
Given the data in the question;
Frequency; [tex]f =1.25 * 10^{18}Hz[/tex]
Time period; [tex]T =\ ?[/tex]
Time period is simply the time taken for one complete cycle of vibration to pass a given point.
It is expressed as:
[tex]T = \frac{1}{f}[/tex]
We substitute our value into the equation
[tex]T = \frac{1}{1.25 * 10^{18}Hz} \\\\T = \frac{1}{1.25 * 10^{18}s^{-1}}\\\\T = 8.0 * 10^{-19}s[/tex]
Therefore, the time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
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