please help me and make it fast.

Answer:
[tex]Accept = 69.44\%[/tex]
[tex]Reject = 11[/tex]
Step-by-step explanation:
Given
See attachment for dataset
Solving (a): Percentage to accept
The percentage to accept are flea collars that range between 14mg to 16mg (inclusive)
From the attachment, we have:
[tex]Total = 36[/tex]
[tex]n(14mg-16mg) =25[/tex] --- Number of 14mg to 16mg
So, the percentage to accept is:
[tex]Accept = \frac{n(14mg-16mg)}{Total} * 100\%[/tex]
[tex]Accept = \frac{25}{36} * 100\%[/tex]
[tex]Accept = 0.6944 * 100\%[/tex]
[tex]Accept = 69.44\%[/tex]
Solving (b): Collars to reject
In (a), we have:
[tex]n(14mg-16mg) =25[/tex]
The number to reject is then calculated by subtracting the collars to accept from the total (this is called complement rule)
So, we have:
[tex]Reject = Total - n(14mg - 16mg)[/tex]
[tex]Reject = 36 - 25[/tex]
[tex]Reject = 11[/tex]
11 will be rejected