Answer:
Step-by-step explanation:
Sample scores : 105, 98, 101, 110, 96, 103, 104, 101, 98, 105, 112, 95, 105, 100, 108
Sample mean, xbar = 102.73
Standard deviation, s = 4.98
H0: μ = 98ttt
H1 : μ ≠98
Test statistic :
(xbar - μ) ÷ s/sqrt(n)
(102.73 - 98) ÷ 4.98 / sqrt(15)
t = 3.655
Pvalue from t score = 0.002599
When. Pvalue < α ; We reject the Null
We can conclude that significant evidence exists that average performance of students is not