Answer:
[tex]HCl conc=2.2M[/tex]
Explanation:
From the question we are told that:
Mass of zinc [tex]Mass_{z_n}=2.5g[/tex]
Initial conc of HCl [tex]HConc_1=6.0M[/tex]
Initial volume of HCl [tex]Hvol_1=20.0mL[/tex]
Molar mass of zinc [tex]M_{Z_n}=65.38g/mol[/tex]
Generally the equation for reaction is mathematically given by
[tex]2HCL+Zn\implies ZnCl_2 +H_2[/tex]
Generally the equation for moles of zinc [tex]m_{z_n}[/tex] is mathematically given by
[tex]m_{z_n}=\frac{Mass_{Z_n}}{M_{Z_n}}[/tex]
[tex]m_{z_n}=\frac{2.5g}{M_{65.38}}[/tex]
[tex]m_{z_n}=0.038molZn[/tex]
Generally the equation for moles of [tex]m_{HCl}[/tex] is mathematically given by
[tex]m_{HCl}=HConc_1*Hvol_1[/tex]
[tex]m_{HCl}=6.0M*20.0mL[/tex]
[tex]m_{HCl}=6.0M*20.0*10^{-3}L[/tex]
[tex]m_{HCl}=0.12\ mol\ HCl[/tex]
Generally the reacted moles of HCl [tex]HCl_[reacted][/tex] is mathematically given by
Since
Zn:HCl =1:2
Therefore
[tex]HCl_[reacted]=0.038*\frac{2}{1}[/tex]
[tex]HCl_[reacted]=0.076mol \ HCl[/tex]
Generally the moles of HCl after Zn oxidization X is mathematically given by
[tex]x=0.12-0.076[/tex]
[tex]x=0.044 mol HCl[/tex]
Generally the conc of hydrochloride acid X is mathematically given by
[tex]X=\frac{0.044}{0.020}[/tex]
[tex]X=2.2 M Hcl[/tex]
Therefore Conc of HCl
[tex]HCl conc=2.2M[/tex]
