Answer:
K.E = 6.4 × 10⁻¹⁶
Velocity = 4.39 × 10⁴ m/sec
Explanation:
From the given information:
The average K.E = P.E (potential energy)
Thus, K.E = q × V
K.E = 1.6 × 10⁻¹⁹ × 4000 V
K.E = 6.4 × 10⁻¹⁶
However,
[tex]K.E = \dfrac{1}{2}mv^2[/tex]
[tex]6.4 \times 10^{-16} = \dfrac{1}{2}(400 \times 1.66 \times 10^{-27} ) \times v^2[/tex]
[tex]\dfrac{6.4 \times 10^{-16} }{\dfrac{1}{2}(400 \times 1.66 \times 10^{-27} )}= v^2[/tex]
[tex]v^2=1.92771084 \times 10^9\\ \\ v=\sqrt{ 1.92771084 \times 10^9} \\ \\ v = 43905.7 \\ \\ \mathbf{v = 4.39 \times 10^4 \ m/sec}[/tex]
