Answer:
[tex]0.54\ \text{m/s}^2[/tex]
Explanation:
F = Force on the sled = 63 N
m = Mass of sled = 28.7 kg
[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.169
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
The force balance of the system is given by
[tex]F-\mu_k mg=ma\\\Rightarrow a=\dfrac{F-\mu_k mg}{m}\\\Rightarrow a=\dfrac{63-0.169\times 28.7\times 9.81}{28.7}\\\Rightarrow a=0.54\ \text{m/s}^2[/tex]
The acceleration of the sled is [tex]0.54\ \text{m/s}^2[/tex].
