Answer:
[tex]22.84\ \text{N}[/tex]
Explanation:
[tex]\rho[/tex] = Density = [tex]7800\ \text{kg/m}^3[/tex]
h = Length of rod = 95 cm
d = Diameter of rod = 2 cm
r = Radius = [tex]\dfrac{d}{2}=1\ \text{cm}[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
V = Volume of rod = [tex]\pi r^2h[/tex]
Mass is given by
[tex]m=V\rho[/tex]
Weight is given by
[tex]w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi\times (1\times 10^{-2})^2\times (95\times 10^{-2})\times 7800\times 9.81\\\Rightarrow w=22.84\ \text{N}[/tex]
The weight of the rod is [tex]22.84\ \text{N}[/tex].
