Respuesta :
Answer:
Step-by-step explanation:
a) Which one is more likely? Explain.
Event A: Randomly selecting a family from the United States that has 3 or more children.
Event B: Randomly selecting 40 families from the United States and finding an average of 3 or more children.
Because the distribution is strongly skewed right, it means families are likely to have more than the mean, 2.5 children. So the probability is high that a randomly selected family will have 3 or more children. But the probability is even higher when 40 families are randomly selected because with a sample size of 40, the results are more likely to follow the main distribution than with a sample size of 1.
For b), because Event B has a larger sample size, its probability can be calculated. With a sample size of 1, it cannot be calculated.
Answer:
Step-by-step explanation:
a. as distribution of number of children per family in the United States is strongly skewed right with a mean of 2.5 children per family and a standard deviation of 1.3 children per family, it is likely that a randomly selecting a family from the United States has 3 or more children.
but if the sample size is increased from a family to 40 families, then it is even more likely because a larger size sample is more likely to follow the distribution. so Event B is more likely
b. Event B's probability calculation requires the right skewness and hence cant be done. but Event A, because its a single family, can be done w/ the mean n SD.
