According to the discrete distribution given, the standard deviation is of 0.95.
The distribution is:
[tex]P(X = 1) = 0.29[/tex]
[tex]P(X = 2) = 0.44[/tex]
[tex]P(X = 3) = 0.19[/tex]
[tex]P(X = 4) = 0.06[/tex]
[tex]P(X = 5) = 0.02[/tex]
The expected value is given by the sum of each value multiplied by it's respective probability, hence:
[tex]E(X) = 0.29(1) + 0.44(2) + 0.19(3) + 0.06(4) + 0.02(5) = 2.08[/tex]
The standard deviation is the square root of the sum of the difference squared of each value and the mean, multiplied by it's respective probability, hence:
[tex]\sqrt{V(X)} = \sqrt{0.29(1-2.08)^2 + 0.44(2-2.08)^2 + \cdots + 0.02(5-2.08)^2} = 0.95[/tex]
The standard deviation is of 0.95.
A similar problem is given at https://brainly.com/question/25653146
