Answer:
[tex](\dfrac{25}{1024})^x[/tex]
Step-by-step explanation:
The given expression is :
[tex](\dfrac{32}{5})^{-2x}[/tex]
We need to rewrite it in the form of [tex]A^x[/tex].
We know that, [tex](\dfrac{1}{x})^{-a}=x^a[/tex]
So,
[tex](\dfrac{32}{5})^{-2x}=(\dfrac{5}{32})^{2x}\\\\=(\dfrac{5^2}{32^2})^x\\\\=(\dfrac{25}{1024})^x[/tex]
So, [tex]A=\dfrac{25}{1024}[/tex]. Hence, this is the required solution.