Answer:
h = 2.5 m
Explanation:
Given that,
Mass of a ball, m = 1.5 kg
Initial velocity of the ball, u = 7 m/s
We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,
[tex]mgh=\dfrac{1}{2}mu^2\\\\h=\dfrac{u^2}{2g}[/tex]
Put all the values,
[tex]h=\dfrac{7^2}{2\times 9.8}\\\\=2.5\ m[/tex]
So, it will reach to a height of 2.5 m.