Assume that BC is tangent to circle A. Find the value of x. Round your answer to the nearest tenth

Answer:
x ≈ 9.6
Step-by-step explanation:
Δ ABC is right with ∠ C = 90° ( angle between tangent and radius )
Using Pythagoras' identity in the right triangle
x² + 14² = 17²
x² + 196 = 289 ( subtract 196 from both sides )
x² = 93 ( take the square root of both sides )
x = [tex]\sqrt{93}[/tex] ≈ 9.6 ( to the nearest tenth )