blossomdrippivn blossomdrippivn

23-04-2021
Mathematics

contestada

If p(x) = 5(x^2 +1) + 16, what is the value of p(11)?
A. 622
B. 736
C. 626
D. 690

Respuesta :

nichealw9 nichealw9

23-04-2021

C. p(11) = 626.

Step-by-step explanation:

Given : p(x) = 5(x²+1)+16.

To find : what is the value of p(11).

Solution : We have given p(x) = 5(x²+1)+16.

For x = 11.

p(11) = 5((11)²+1)+16.

p(11) = 5 ( 121 + 1 ) +16.

p(11) = 5 (122) + 16.

p(11) = 610 + 16.

p(11) = 626.

Therefore, p(11) = 626.

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