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The power source in a particular welding setup generates 3,066 watts that can be transferred to the work surface with a heat transfer factor of 0.85. The metal to be welded is a medium-carbon steel which has a melt temperature of 1,700 K, or 3,060 R. The melting factor in the operation is 0.6. A continuous fillet weld is to be made with a cross-sectional areas of 25 mm2. Determine the travel speed in mm/s at which the welding operation can be accomplished

Respuesta :

batolisis

Answer:

travel speed = 10.10 mm/s

Explanation:

Given data:

power generated ( P ) = 3066 watts

heat transfer factor ( ηf ) = 0.85

melt temperature of the medium-carbon steel ( Tm )  = 1700 K

melting factor ( mf ) = 0.6

Cross sectional area of a continuous fillet ( A )  = 25 mm^2

To Calculate the travel speed at which the welding operation

Travel speed ( Ts ) = ?

we will use the formula below

mf * ηf * P = H/V * A * Ts ------- ( 1 )

where H/V = C * S * Tm

C = 470 J/kg-k  (  value gotten from table )

S = 7750 kg/m^3  ( value gotten from table )

back to equation 1

0.6 * 0.85 * 3066 = ( 470 * 7750 *1700 * 10^-3 )  * 25 * Ts

∴ Ts = 1563.66 / ( 6.19225 * 25 )

       = 10.10  mm/sec

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