∠X=5x+30
∘
\angle \mathrm{Y}=3\mathrm{x}+60^{\circ}∠Y=3x+60
∘

Corresponding angles on parallel lines cut by a transversal are equal
5x + 30 = 3x + 60
Subtract 3x from both sides
2x + 30 = 60
Subtract 30 from both sides
2x = 30
Divide both sides by 2
X = 15