Answer:
Tthe frequency of the green-winged allele in the next generation will be 46%
Explanation:
For a trait controlled by a pair of alleles A and a in a given population of organisms, the Hardy-Weinberg equilibrium equation is given as:
p² + 2pq + q² = 1; also p + q = 1
Where, p² gives the frequency of h0m0zygous dominant (AA) individuals in a population, 2pq gives the frequency of heterozygous (Aa) individuals, and q² gives the frequency of h0m0zygous recessive (aa) individuals. Also, p gives the frequency of the dominant allele and q is the frequency of the recessive allele in the given population.
In the given population of moths, the green-winged allele is recessive while the brown-winged allele is dominant. When a Hardy-Weinberg equilibrium is established, the frequency of moth h0m0zygous for the recessive allele in the population is 21%.
This means that, q² = 21% = 0.21
The frequency of the green-winged (recessive) allele is q.
Since q² = 0.21
q = √0.21
q = 0.46 = 46%
Therefore, the frequency of the green-winged allele in the next generation will be 46%
The frequency of the green-winged allele in the next generation will be 46%.
If the population is now in Hardy-Weinberg equilibrium, what will be the frequency of the green-winged allele in the next generation using the given information.
that, q² = 21% = 0.21
The frequency of the green-winged (recessive) allele is q.
Since q² = 0.21
q = √0.21
q = 0.46 = 46%
The Hardy-Weinberg equilibrium is a principle saying that the genetic variation in a population will remain consistent from one generation to the next in the absence of disturbing factors.
Thus, the frequency of the green-winged allele in the next generation will be 46%
To learn more about Hardy-Weinberg equilibrium click here:
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