An expression is given that has a value between 4.44.4 and 4.54.5, and where xx represents an integer. ​ ​ \sqrt{x}+\sqrt{x} x ​ + x ​ ​ What is the value of xx?

Respuesta :

Answer:

[tex]x = 5[/tex]

Step-by-step explanation:

Given

[tex]\sqrt x + \sqrt x = (4.4,4.5)[/tex]

Required

Find x

When the result is 4.4, we have:

[tex]\sqrt x + \sqrt x = 4.4[/tex]

This gives:

[tex]2\sqrt x = 4.4[/tex]

Divide both sides by 2

[tex]\sqrt x = 2.2[/tex]

Square both sides

[tex]x = 2.2^2[/tex]

[tex]x = 4.84[/tex]

When the result is 4.5, we have:

[tex]\sqrt x + \sqrt x = 4.5[/tex]

[tex]2\sqrt x = 4.5\\[/tex]

Divide both sides by 2

[tex]\sqrt x = 2.25[/tex]

Square both sides

[tex]x = 2.25^2[/tex]

[tex]x = 5.0625[/tex]

So, the value of x is between 4.84 and 5.0625

i.e.

[tex]x = (4.84,5.0625)[/tex]

The only integer between the above interval is 5.

Hence:

[tex]x = 5[/tex]