Respuesta :
Answer:
2.75 × 10⁻⁶ M/s
1.69 × 10⁻⁶ M/s
9.23 × 10⁻⁻⁷ M/s
4.43 × 10⁻⁻⁷ M/s
2.1 × 10⁻⁻⁷ M/s
Explanation:
We have the following information for the isomerization of methyl isonitrile
Time (s) [CH₃NC] (M)
0 0.0165
2000 0.0110
5000 0.00591
8000 0.00314
12000 0.00137
15000 0.00074
To calculate the average rate of reaction (r) for each interval, we need to use the following expression:
r = -Δ[CH₃NC]/Δt
Interval 0-2000 s
r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s
Interval 2000-5000 s
r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s
Interval 5000-8000 s
r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s
Interval 8000-12000 s
r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s
Interval 12000-15000 s
r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s
The average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
From the question,
We are to calculate the average rate of reaction for each of the measurement.
First, we will create a proper table for the data
Time (s) [CH3NC] (M)
0 0.0165
2,000 0.0110
5,000 0.00591
8,000 0.00314
12,000 0.00137
15,000 0.00074
The average rate of reaction is given by the formula
[tex]Average\ rate\ of\ reaction = \frac{Final\ concentration - Initial\ concentration}{Final\ time - Initial\ time}[/tex]
1.
[tex]Average\ rate\ of\ reaction = \frac{0.0110-0.0165}{2000 -0 }[/tex]
Average rate of reaction = 2.75×10⁻⁶ M/s
2.
[tex]Average\ rate\ of\ reaction = \frac{0.00591-0.0110}{5000 -2000 }[/tex]
Average rate of reaction = 1.70×10⁻⁶ M/s
3.
[tex]Average\ rate\ of\ reaction = \frac{0.00314-0.00591}{8000 -5000 }[/tex]
Average rate of reaction = 9.23×10⁻⁷ M/s
4.
[tex]Average\ rate\ of\ reaction = \frac{0.00137-0.00314}{12000 -8000 }[/tex]
Average rate of reaction = 4.43×10⁻⁷ M/s
5.
[tex]Average\ rate\ of\ reaction = \frac{0.00074-0.00137}{15000 -12000 }[/tex]
Average rate of reaction = 2.10×10⁻⁷ M/s
Hence, the average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
Learn more here: https://brainly.com/question/14189499
