What is the [OH-] in a solution that has a pH = 9.23? *
O 1.7x10^5
O 8.2x10^-9
1.7x10^--5 M.

Answer: 1.7x10^-5
Explanation:
pH + pOH = 14
14 - pH = pOH
14 - 9.23 = 4.77
pOH =4.77
[OH-] = 10^-pOH
= 10^-4.77
= 1.698243x10^-5
= 1.7x10^-5