Answer:
Acceleration is 0.5 m/s² and the distance covered is 6.25 m.
Step-by-step explanation:
Given that,
Initial speed, u = 0
Final speed, v = 9 km/h = 2.5 m/s
Time, t = 5 seconds
We need to find the acceleration and the displacement covered in that time. Acceleration = rate of change of velocity
So,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{2.5-0}{5}\\\\a=0.5\ m/s^2[/tex]
Distance d can be calculated using third equation of motion.
[tex]d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{2.5^2-0^2}{2\times 0.5}\\\\d=6.25\ m[/tex]
So, acceleration is 0.5 m/s² and the distance covered is 6.25 m.
