Answer:
The value of the test statistic is z = -4.19.
Step-by-step explanation:
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the expected value for the population mean, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
Average 13.5 years of experience in their specialties, with a standard deviation of 7.6 years.
This means that [tex]\mu = 13.5, \sigma = 7.6[/tex]
A random sample of 150 doctors from HMOs shows a mean of only 10.9 years of experience.
This means that [tex]n = 150, X = 10.9[/tex]
What is the test statistic?
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{10.9 - 13.5}{\frac{7.6}{\sqrt{150}}}[/tex]
[tex]z = -4.19[/tex]
The value of the test statistic is z = -4.19.
