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If 3.25 moles of Ar occupies 100.L at a certain temperature and pressure, what volume does 14.15 moles of Ar occupy?

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sebassandin

Answer:

[tex]V_2=435.4L[/tex]

Explanation:

Hello there!

In this case, for this gas problem, we can use the Avogadro's law as a way to understand the volume-mole behavior as a directly proportional relationship:

[tex]\frac{V_2}{n_2}=\frac{V_1}{n_1}[/tex]

Thus, given the initial and final moles and the initial volume, we obtain the following final volume:

[tex]V_2=\frac{V_1n_2}{n_1} =\frac{100.L*14.15mol}{3.25mol}\\\\V_2=435.4L[/tex]

Best regards.

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