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Ans: 47,070 J


Thus, 47,070 J are needed to increase the temperature of 150 g of water from 25 degrees C to its boiling point of 100 degrees C. One can follow a similar procedure to determine the energy needed to heat water from one temperature to another.

The amout of energy which are required to boil 150 grams of water is 47,092.5 Joules.

How do we calculate the absorbed heat?

Amount of heat which is absorbed by the water to boil at 100°C is calculated by using the below formula as:
Q = mcΔT, where

m = mass of water = 150g

c = specific heat of water = 4.186 J/g.°C

ΔT = change in temperature = 100°C - 25°C = 75 °C

On putting values on the above equation, we get

Q = (150)(4.186)(75) = 47,092.5 Joules

Hence required amount of heat is 47,092.5 joules.

To know more about absorbed heat, visit the below link:
https://brainly.com/question/16559442

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