Answer:
[tex]\lim_{x \to 0} sin^2(x)tan(x) = 0[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Pre-Calculus
Calculus
Step-by-step explanation:
Step 1: Define
[tex]\lim_{x \to 0} (sinx)^2tanx[/tex]
Step 2: Solve
- Rewrite [Sine Trig]: [tex]\lim_{x \to 0} sin^2(x)tan(x)[/tex]
- Evaluate limit [Substitute in x: [tex]\lim_{x \to 0} sin^2(x)tan(x) = sin^2(0)tan(0)[/tex]
- Evaluate trig: [tex]\lim_{x \to 0} sin^2(x)tan(x) = 0 \cdot 0[/tex]
- Multiply: [tex]\lim_{x \to 0} sin^2(x)tan(x) = 0[/tex]
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Limits
Book: College Calculus 10e
