Answer:
a) t= 2hours and 10 minutes
b) t=4hours and 20 minutes
v1t1=v2t2
Answer:
Step-by-step explanation:
rate = distance / time distance is constant (a-b) so call it D
time = distance / rate rate = speed (ie miles per hour = mph)
time = distance / speed
A) if the new speed is 1.5 of the original speed
original time = 3.25 hours or 195 minutes
3.25 = D / 1 new time = D/1.5 find new time
3.25 is to D as new time is to D/1.5
3.25/D = new time / D/1.5 multiple D/1.5 on both sides
(3.25/D) ( D/1.5) = new time the distance D cancels
3.25 (D / D) / 1.5 = new time
3.25 / 1.5 = 2.167 hours or 2 hours and 10 minutes
B) if the speed is 3/4 the original speed
original time = 3.25 hours or 195 minutes
3.25 = D / 1 new time = D/(3/4) find new time
3.25 is to D as new time is to D/0.75
3.25/D = new time / D/0.75 multiple D/0.75 on both sides
(3.25/D) ( D/0.75) = new time
3.25 (D / D) / 0.75 = new time
3.25 / 0.75 = 4.333 hours or 4 hours and 20 minutes
