Respuesta :
Answer:
[tex] \sqrt{125 } \\ = 11.18[/tex]
It is in between 0 to 12.
Answer:
√125 must be between 11 and 12.
Step-by-step explanation:
Identify perfect squares in the neighborhood of 125:
121 = 11^2 or √121 = 11
144 = 12^2 √144 = 12
√125 must therefore be between 11 and 12.