The new volume of the neon gas as its temperature is reduced is 2.29L.
Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.
It is expressed as;
V₁/T₁ = V₂/T₂
Given the data in the question;
To determine the new volume of the neon gas, we substitute our given values into the expression above.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂ / T₁
V₂ = ( 2.5L × 298.15K ) / 325.15K
V₂ = 745.375LK / 325.15K
V₂ = 2.29L
Therefore, the new volume of the neon gas as itstemperature is reduced is 2.29L.
Learn more about Charles's law here: brainly.com/question/12835309
