Respuesta :

siya90258

[tex]cdb = 8 \\ x = 4 \\ by \: pythagoras \: theorem \\ 8 {}^{2} = 4 {}^{2} + x{}^{2} \\ 64 = 16 + x {}^{2} \\ 64 - 16 = x {}^{2} \\ 48 = x{}^{2} \\ \sqrt{48 } = x\\ angle \: b = 60 \\ angle \: of \: equilateral \: triangle \: equal \: 60[/tex]

Otras preguntas